AP Physics 2 · Topic 11.2

Topic 11.2: Simple Circuits

Unit 11: Electric Circuits15-18% of the multiple-choice section

A circuit is composed of electrical loops built from elements like wires, batteries, resistors, bulbs, capacitors, switches and meters. A closed circuit lets charge flow, an open one does not, and a short lets charge flow with no change in potential difference. The schematic is what you read.

AP Physics: Unit 11 (topics 11.2 Simple Circuits). AP Physics 2 Unit 11, Topic 11.2. The single learning objective, 11.2.A, asks students to describe the behavior of a circuit. Four essential knowledge statements support it: 11.2.A.1 defines a circuit as composed of electrical loops; 11.2.A.2 defines a closed electrical loop, with sub-statements defining a closed circuit as one in which charges would be able to flow, an open circuit as one in which they would not, and a short circuit as one in which charges would be able to flow with no change in potential difference; 11.2.A.3 states that a single circuit element may be part of multiple electrical loops; and 11.2.A.4 makes circuit schematics the representation used to describe and analyze circuits, adding that a circuit's properties depend on the physical arrangement of its elements (11.2.A.4.i) and giving the common symbols (11.2.A.4.ii). The boundary statement reads: unless otherwise specified, all circuit schematic diagrams will be drawn using conventional current. No equation is printed anywhere in this topic. The CED's suggested skills here are 1.A, 2.C, 3.B, and 3.C. Unit 11 carries 15 to 18 percent of the multiple-choice section and a suggested 12 to 20 class periods.

What Topic 11.2 requires

Topic 11.2 carries one learning objective, 11.2.A: describe the behavior of a circuit. Four essential knowledge statements sit under it, and two of them add sub-statements.

  • 11.2.A.1 A circuit is composed of electrical loops, which may include circuit elements such as wires, batteries, resistors, lightbulbs, capacitors, switches, ammeters, and voltmeters.
  • 11.2.A.2 A closed electrical loop is a closed path through which charges may flow.
  • 11.2.A.2.i A closed circuit is one in which charges would be able to flow.
  • 11.2.A.2.ii An open circuit is one in which charges would not be able to flow.
  • 11.2.A.2.iii A short circuit is one in which charges would be able to flow with no change in potential difference.
  • 11.2.A.3 A single circuit element may be part of multiple electrical loops.
  • 11.2.A.4 Circuit schematics are representations used to describe and analyze electric circuits.
  • 11.2.A.4.i The properties of an electric circuit are dependent on the physical arrangement of its constituent elements.
  • 11.2.A.4.ii Circuit elements have common symbols that are used to create schematic diagrams. Variable elements are indicated by a diagonal strikethrough arrow across the standard symbol for that element.

The topic's boundary statement is a single sentence: unless otherwise specified, all circuit schematic diagrams will be drawn using conventional current.

That is why a bare arrow on a wire in an AP Physics 2 diagram needs no caption. It is conventional current, the direction positive charge would move, which is Topic 11.1's essential knowledge 11.1.A.2.i. The exception clause carries as much weight as the rule: a question is free to specify otherwise, and then the arrow means whatever the question says it means.

The CED lists four suggested skills here, and they are the same four it lists for Topic 11.1, where the full wording is set out: 1.A, create diagrams, tables, charts, or schematics; 2.C, compare physical quantities between scenarios or at different times; 3.B, apply a law, definition, theoretical relationship, or model to make a claim; and 3.C, justify or support a claim using evidence. Unit 11 is weighted at 15 to 18 percent of the multiple-choice section, with roughly 12 to 20 suggested class periods.

Now notice something about that list: Topic 11.2 prints no equation at all. Other topics in this unit print a relevant equation beside an essential knowledge statement; this one does not. The assessable content is definitions, loop structure and reading a representation.

A circuit is a set of loops, not a list of parts (11.2.A.1 and 11.2.A.3)

The CED's definition leads with the loops and treats the hardware as filling: a circuit is composed of electrical loops, which may include circuit elements such as wires, batteries, resistors, lightbulbs, capacitors, switches, ammeters, and voltmeters. Note the phrase "may include". The elements are the contents; the loop is the thing.

That ordering pays off immediately, because 11.2.A.3 says a single circuit element may be part of multiple electrical loops. A battery feeding two branches belongs to both, and a resistor in the trunk of a circuit that splits downstream belongs to every loop running through that trunk. Elements are not privately owned, so a change in one loop can reach another through a shared element.

To count loops on a diagram, trace with a finger. Start anywhere, move only along wires and through elements, and see whether you can return to your starting point without reusing a wire. Each distinct route that closes is a loop. One battery and one resistor gives exactly one. Split the path into two branches and you can trace three closed routes: one through each branch, and one that runs down one branch and back up the other without touching the source at all. That third route is a genuine loop, and Kirchhoff's loop rule applies to it just as it does to the other two.

Two consequences for reading a diagram. Count paths before you count parts, because how many routes charge can take decides whether elements share a current or share a potential difference. And a break matters only where it breaks a loop: opening a switch in a single-loop circuit stops everything, while opening one in a branch stops that branch and leaves any loop that avoids it intact. That is the physics behind the unit's essential question about why several bulbs on a string of lights go out when one bulb is unplugged.

Closed, open and short: the three states the CED names (11.2.A.2)

Essential knowledge 11.2.A.2 defines the loop itself: a closed electrical loop is a closed path through which charges may flow. Three sub-statements then name the three states you are expected to identify.

StateThe CED's wordingWhat it looks like on a diagramCurrent
Closed"A closed circuit is one in which charges would be able to flow" (11.2.A.2.i)An unbroken loop, every switch in it closedNonzero, set by the elements in the loop
Open"An open circuit is one in which charges would not be able to flow" (11.2.A.2.ii)A gap: an open switch, a broken filament, a lead pulled off a terminalZero in any loop that the gap breaks
Short"A short circuit is one in which charges would be able to flow with no change in potential difference" (11.2.A.2.iii)A path of negligible resistance laid alongside an element, or straight across the sourceNonzero along the short; the element it bypasses carries none

Two features of that wording are worth pausing on.

First, all three sub-statements are written in the conditional: charges would be able to flow, or would not. They describe what the path permits, not whether anything is flowing right now. A closed loop with no source in it is still a closed circuit. Getting this right keeps you from calling a circuit "open" merely because the current happens to be zero.

Second, the CED defines a short by its potential difference, not by heat, sparks or a large current. In an exam circuit the wires are ideal, so any ideal wire connected across an element shorts that element: the two ends are joined by a path with zero potential difference between them, so the element has zero potential difference across it and therefore no current through it. The third worked example below walks that through with numbers.

The schematic is a representation, and it is the one you are graded on (11.2.A.4)

Essential knowledge 11.2.A.4 says circuit schematics are representations used to describe and analyze electric circuits, and 11.2.A.4.ii supplies the symbol set. The CED prints seven.

ElementThe symbol as the CED prints it
BatteryA stack of parallel lines of alternating length crossing the wire
BulbA circle with a filament loop drawn inside it
SwitchA break between two contact dots, with a hinged line lifted away from one of them
CapacitorTwo equal parallel lines with a gap between them
ResistorA zigzag in the wire
AmmeterA circle containing the letter A
VoltmeterA circle containing the letter V

Two details of that set repay a second look. The switch is drawn in the open position, so the symbol tells you the state as well as the element. And the capacitor's two lines are the same length while the battery's alternate long and short, which is the difference to check when either is drawn small.

11.2.A.4.ii also gives the one modifier the CED defines: variable elements are indicated by a diagonal strikethrough arrow across the standard symbol for that element. A resistor zigzag with a diagonal arrow through it is a variable resistor. That arrow is not a current arrow and does not point anywhere in the circuit.

The deeper point in 11.2.A.4 is that a schematic is a topological drawing. It records which elements are joined to which, not how long the wires are or where anything sits on the page. Two diagrams that look nothing alike are the same circuit when the connections match, and two that look almost identical are different circuits when one wire moves. Wire length carries no meaning: Topic 11.5's essential knowledge 11.5.B.1 says ideal wires have negligible resistance.

Suggested skill 1.A is listed first for this topic, and turning a verbal description into a correct schematic is its most direct form. Practise it in both directions.

Reading a single-loop schematic

The smallest circuit that does anything is an ideal battery, a resistor and the wires joining them: one loop, one current, and every element carries that same current because there is nowhere else for charge to go. Read a diagram like this in a fixed order.

  1. Find the source and its terminals. By the usual drafting convention the longer line of the battery symbol is the higher-potential terminal. The CED prints the symbol without a plus or minus label, so identify the terminals from the labels or the current arrow a question supplies rather than from memory.
  2. Fix the direction of the current. The boundary statement settles it: unless otherwise specified, the diagram uses conventional current. It runs out of the higher-potential terminal, around the external part of the loop, and back into the other terminal.
  3. Look for breaks and shortcuts. One open switch anywhere in a single-loop circuit makes the whole thing open and the current zero (11.2.A.2.ii). Any element with an ideal wire across it is shorted, so it carries no current and has no potential difference across it (11.2.A.2.iii).
  4. Walk the loop and track the potential. It rises across the battery from the lower-potential terminal to the higher, drops across the resistor in the direction of the conventional current, and does not change along an ideal wire.

That last step is the informal version of a rule you meet formally in Topic 11.6. The reason the rises and drops must cancel over a complete loop is conservation of energy, which is what the unit opener means when it says Unit 11 revisits the behavior of charged particles to deepen students' understanding of the law of conservation of energy and its application to electric circuits.

To turn a single-loop schematic into a number for the current you need Ohm's law, and Ohm's law is Topic 11.3. The AP Physics 2 sheet prints it as I=ΔVRI = \frac{\Delta V}{R}, with the delta, because the numerator is a potential difference. The worked examples below use it purely as a tool so a schematic can produce a number; resistance, resistivity and what makes an element ohmic belong to 11.3, and the step-by-step routine lives in the Ohm's law guide and the Ohm's law calculator.

The arrangement is the circuit (11.2.A.4.i)

Essential knowledge 11.2.A.4.i is one line long: the properties of an electric circuit are dependent on the physical arrangement of its constituent elements.

It is the whole reason schematics exist. A parts list is not a circuit. One battery and two resistors can be wired as a single loop or with each resistor straight across the battery's terminals, and the two circuits differ in the current the battery delivers, the potential difference across each resistor, and what happens when one is removed. The second worked example below puts a factor of four between the two battery currents.

Two habits follow from taking 11.2.A.4.i seriously.

  • Decide what is joined to what before computing anything. Reading the arrangement is a separate step from calculating, and doing it second is where avoidable errors enter.
  • When a question changes the circuit, redraw it. A bulb removed, a switch thrown, a wire added: each is a new schematic. The unit's Developing Understanding note is explicit that students must be able to articulate the impact of a light bulb being removed from a circuit, which is a question about arrangement rather than arithmetic.

One of the unit's essential questions lands here: "Why do several bulbs on a string of lights go out when one bulb is unplugged?" is 11.2.A.4.i and 11.2.A.2.ii together, since unplugging a bulb opens a loop and whether other bulbs go dark depends on whether they sit in it.

Systematic reduction of series and parallel groups is Topic 11.5's content, and the routine for it is in the series vs parallel guide. Topic 11.2 sits one level above: recognise that the arrangement is itself a property of the circuit, and read it correctly off the diagram before any formula comes out.

What "ideal" means here, and where the CED spells it out

Every element in a Topic 11.2 problem is ideal unless the question says otherwise, and that is printed rather than assumed. The AP Physics 2 Table of Information carries nine conventions used on the exam unless otherwise stated, and three of them govern circuits:

  • "Strings, springs, batteries, wires, and meters are ideal."
  • "Resistors and lightbulbs are ohmic."
  • "Capacitors are air-filled (κ=1.0\kappa = 1.0)."

The CED spells out what ideal means in Topic 11.5 rather than here. Essential knowledge 11.5.B.1 states that ideal batteries have negligible internal resistance and ideal wires have negligible resistance; 11.5.C.1.ii, that ideal ammeters have zero resistance so that they do not affect the current in the element they are in series with; and 11.5.C.2.ii, that ideal voltmeters have an infinite resistance so that no charge flows through them. The Topic 11.5 boundary statement then restates the default in the CED's own voice: AP Physics 2 only expects students to qualitatively discuss how a nonideal ammeter or voltmeter will affect the results of measurements; unless otherwise stated, all batteries, wires, and meters are assumed to be ideal; and circuits with batteries of different potential differences connected in parallel will not be assessed.

For reading a Topic 11.2 diagram, three consequences do the work.

  • An ideal battery holds the same potential difference across its terminals whatever current the circuit draws, having no internal resistance for the current to drop potential across.
  • An ideal wire has no potential difference across it however much current it carries. That is why an ideal wire laid across an element produces a short circuit in the sense of 11.2.A.2.iii, and why connecting-wire resistance never enters the arithmetic.
  • An ideal meter does not disturb what it measures.

None of these are approximations you invent to make a problem tractable. They are stated conventions, so you can cite them in a justification instead of apologising for them.

How Topic 11.2 is tested, and where it leads

The four suggested skills describe four things a question can ask.

  • 1.A Draw the schematic for a described circuit, with correct symbols and correct connections.
  • 2.C Compare two scenarios: before and after a switch is thrown, or two arrangements of the same components side by side.
  • 3.B Apply the definitions in 11.2.A.2: classify the circuit, then claim what the current does.
  • 3.C Justify that claim, with the schematic itself as the physical representation you cite.

Because Topic 11.2 has no equation, its questions tend to be verbal, and the unit's Preparing for the AP Exam note warns that students should know the differences in meaning between "current", "potential difference", "resistance", "resistivity", and "capacitance". Saying "no voltage flows", or "there is no current because the circuit is shorted", is the kind of wording that loses justification points even when the underlying idea is right.

Where the topic leads:

  • Topic 11.3 supplies the relationship between current, potential difference and resistance that turns a schematic into numbers, and Topic 11.4 adds the rate at which an element transfers energy.
  • Topic 11.5 generalises the single loop to compound circuits, and defines ideal batteries, wires and meters.
  • Topic 11.6 and Topic 11.7 turn loop tracing and junction counting into rules.
  • Topic 11.8 puts a capacitor from Topic 10.6 into the loop, at which point the current stops being steady.

Reading a single-loop schematic with the switch open and closed

A schematic shows one loop containing an ideal 4.5 V battery, a switch, and a 60 Ω resistor, joined by ideal wires. Identify the elements from their symbols, state the direction of the current, find the current with the switch closed and with the switch open, and find the charge that passes through the resistor in 10.0 s with the switch closed.

  1. Name the elements from the symbol set in 11.2.A.4.ii: the stack of alternating long and short lines is the battery, the zigzag is the resistor, and the hinged line between two contact dots is the switch.

  2. Count the loops. One route passes through all three elements and returns to its start, and there is no second. A single loop means a single current, carried by every element in it.

  3. Direction. The boundary statement says the diagram uses conventional current unless otherwise specified, so the current runs out of the higher-potential terminal, through the switch and the resistor, and back into the other terminal.

  4. Switch closed: the loop is unbroken, so this is a closed circuit and charges are able to flow (11.2.A.2.i). Using Ohm's law from Topic 11.3, I=ΔV/R=(4.5V)/(60Ω)=0.075AI = \Delta V / R = (4.5 \, \mathrm{V})/(60 \, \Omega) = 0.075 \, \mathrm{A}, which is 75 mA.

  5. Switch open: the loop has a gap, so this is an open circuit and charges are not able to flow (11.2.A.2.ii). The current is zero everywhere in the loop, the resistor included, because there is no alternative path.

  6. Charge in 10.0 s with the switch closed, using Topic 11.1's definition rearranged as Δq=IΔt\Delta q = I \Delta t: Δq=(0.075A)(10.0s)=0.75C\Delta q = (0.075 \, \mathrm{A})(10.0 \, \mathrm{s}) = 0.75 \, \mathrm{C}.

A single loop with an ideal battery, a switch and a resistor, carrying conventional current out of the higher-potential terminal and around the loop. Switch closed: I=0.075AI = 0.075 \, \mathrm{A} (75 mA) in every element, and Δq=0.75C\Delta q = 0.75 \, \mathrm{C} through the resistor in 10.0 s. Switch open: I=0I = 0.

Same parts, two arrangements, four times the current

You have an ideal 4.5 V battery and two 30 Ω resistors. Arrangement A wires them into a single loop with the battery. Arrangement B connects each resistor directly across the battery's terminals. For each arrangement, count the closed paths you can trace, say which elements belong to more than one loop, and find the current the battery delivers.

  1. Arrangement A. Trace once and you return to your start; there is no second route, so there is exactly one closed path and all three elements sit in it. One loop means one current through everything.

  2. Resistances in a single loop add, so the loop presents 30+30=60Ω30 + 30 = 60 \, \Omega and I=(4.5V)/(60Ω)=0.075AI = (4.5 \, \mathrm{V})/(60 \, \Omega) = 0.075 \, \mathrm{A}. Each resistor carries all of that, and each has ΔV=(0.075A)(30Ω)=2.25V\Delta V = (0.075 \, \mathrm{A})(30 \, \Omega) = 2.25 \, \mathrm{V} across it. The two drops total 4.5 V, the whole of the battery's potential difference, as a complete loop requires.

  3. Arrangement B. Each resistor is joined straight across the battery's terminals. Trace from the battery through the first resistor and back: that closes. Through the second and back: that closes too. You can also trace down through one resistor and up through the other without passing the battery, which closes as well. Three closed paths, two containing the battery.

  4. Every element here is shared: the battery belongs to two of the three loops, and so does each resistor. That is 11.2.A.3, a single circuit element may be part of multiple electrical loops, made concrete.

  5. Because each resistor is directly across the terminals, each has the full 4.5 V across it, so each carries I=(4.5V)/(30Ω)=0.15AI = (4.5 \, \mathrm{V})/(30 \, \Omega) = 0.15 \, \mathrm{A}. The battery supplies both branches, so it delivers 0.15+0.15=0.30A0.15 + 0.15 = 0.30 \, \mathrm{A}.

  6. Compare. Same battery, same two resistors, and the battery current goes from 0.075 A to 0.30 A, a factor of four. Nothing about the parts changed, only the arrangement, which is 11.2.A.4.i written as a number.

Arrangement A: one closed path, I=0.075AI = 0.075 \, \mathrm{A} through every element, 2.25 V across each resistor. Arrangement B: three closed paths with every element shared, 4.5 V across each resistor, 0.15 A per branch and 0.30 A from the battery, four times A's current from identical parts.

Shorting out one element

A single loop contains an ideal 4.5 V battery, a 60 Ω resistor and a 20 Ω resistor. A student then connects an ideal wire directly across the 20 Ω resistor. Find the current and the potential difference across each resistor before and after, and explain why the added wire fits the CED's definition of a short circuit.

  1. Before. One loop, so the resistances add: 60+20=80Ω60 + 20 = 80 \, \Omega, and I=(4.5V)/(80Ω)=0.05625AI = (4.5 \, \mathrm{V})/(80 \, \Omega) = 0.05625 \, \mathrm{A}, or 0.056A0.056 \, \mathrm{A} to two significant figures.

  2. Potential differences before: (0.05625A)(60Ω)=3.375V(0.05625 \, \mathrm{A})(60 \, \Omega) = 3.375 \, \mathrm{V} across the 60 Ω resistor and (0.05625A)(20Ω)=1.125V(0.05625 \, \mathrm{A})(20 \, \Omega) = 1.125 \, \mathrm{V} across the 20 Ω resistor. They total 4.500 V, the battery's potential difference, which checks the loop bookkeeping.

  3. After. The added wire is ideal, so there is no change in potential difference along it. It joins the same two points as the 20 Ω resistor, so those points are now at the same potential and the resistor has zero potential difference across it as well. That is essential knowledge 11.2.A.2.iii exactly: charges flow along the added path with no change in potential difference, so the wire is a short circuit across the 20 Ω resistor.

  4. With no potential difference across it, the 20 Ω resistor carries no current, and all of the current takes the ideal wire instead. The loop now presents the 60 Ω resistor alone, so I=(4.5V)/(60Ω)=0.075AI = (4.5 \, \mathrm{V})/(60 \, \Omega) = 0.075 \, \mathrm{A}, with the full 4.5 V across it and zero across both the 20 Ω resistor and the shorting wire.

  5. Compare. The current rose from 0.056 A to 0.075 A, by a factor of 80/60=4/380/60 = 4/3. Note what did not change: the battery is ideal, so it still holds 4.5 V across its terminals whatever the circuit draws.

Before: I=0.056AI = 0.056 \, \mathrm{A}, with 3.4 V across the 60 Ω resistor and 1.1 V across the 20 Ω resistor. After: I=0.075AI = 0.075 \, \mathrm{A}, the full 4.5 V across the 60 Ω resistor, and zero across the shorted 20 Ω resistor, which now carries no current. The added wire is a short in the CED's sense: charges flow along it with no change in potential difference.

Frequently asked questions

What is a circuit in AP Physics 2?

Essential knowledge 11.2.A.1 defines a circuit as composed of electrical loops, which may include elements such as wires, batteries, resistors, lightbulbs, capacitors, switches, ammeters, and voltmeters. The loop is what makes it a circuit: 11.2.A.2 defines a closed electrical loop as a closed path through which charges may flow, and 11.2.A.3 adds that one element can belong to several loops.

What is the difference between an open circuit and a closed circuit?

A closed circuit is one in which charges would be able to flow, and an open circuit is one in which charges would not be able to flow. Those are essential knowledge 11.2.A.2.i and 11.2.A.2.ii of AP Physics 2. On a diagram an open circuit shows a gap in the loop, usually an open switch or a disconnected lead, and the current in any loop the gap breaks is zero. Both definitions describe what the path would permit, so a closed loop with no source in it still counts as closed.

What is a short circuit in AP Physics 2?

Essential knowledge 11.2.A.2.iii defines a short circuit as one in which charges would be able to flow with no change in potential difference. The definition is about potential difference, not heat or sparks. Because exam wires are ideal, an ideal wire across an element shorts it: both ends sit at the same potential, so the element has zero potential difference across it and carries no current, and the current takes the wire instead.

What do the symbols on an AP Physics 2 circuit diagram mean?

Essential knowledge 11.2.A.4.ii prints seven symbols: a stack of parallel lines of alternating length for a battery, a circle with a filament loop for a bulb, a hinged line between two contact dots for a switch (drawn open), two equal parallel lines with a gap for a capacitor, a zigzag for a resistor, a circle with an A for an ammeter, and a circle with a V for a voltmeter. A diagonal strikethrough arrow across a symbol marks a variable element.

Which way does the current arrow point on an AP Physics 2 circuit diagram?

In the direction of conventional current, the way positive charge would move. The AP Physics 2 Topic 11.2 boundary statement says that unless otherwise specified, all circuit schematic diagrams will be drawn using conventional current, and the exam's Table of Information lists "Current is conventional current" among the conventions used unless otherwise stated. In a metal wire the electrons drift the opposite way (11.1.A.2.ii), but the arrow still shows conventional current.

What does it mean for a battery to be ideal on the AP Physics 2 exam?

An ideal battery has negligible internal resistance, which is essential knowledge 11.5.B.1, so it holds the same potential difference across its terminals no matter how much current the circuit draws. The AP Physics 2 Table of Information lists "Strings, springs, batteries, wires, and meters are ideal" among the conventions used unless otherwise stated, and the Topic 11.5 boundary statement repeats it. Batteries with internal resistance belong to Topic 11.5.

Why does rearranging the same components change the circuit?

Because the arrangement is itself a property of the circuit. Essential knowledge 11.2.A.4.i states that the properties of an electric circuit are dependent on the physical arrangement of its constituent elements. One battery and two identical resistors wired as a single loop give one current through everything and split the battery's potential difference. The same parts with each resistor straight across the terminals put the full potential difference across each, and multiply the battery's current.