AP Physics 2 · Unit 12 of 7

Unit 12: Magnetism and Electromagnetism

12-15% of the multiple-choice section4 topics

Topics in this unit

  1. 12.1Magnetic Fields
  2. 12.2Magnetism and Moving Charges
  3. 12.3Magnetism and Current-Carrying Wires
  4. 12.4Electromagnetic Induction and Faraday's Law

Magnetism and Electromagnetism is Unit 12 of AP Physics 2, worth 12 to 15 percent of the multiple-choice section over about 10 to 14 class periods. One idea runs through all four topics: moving charge makes a magnetic field, and a changing magnetic flux drives a current.

AP Physics: Unit 12 (topics 12.1 Magnetic Fields, 12.2 Magnetism and Moving Charges, 12.3 Magnetism and Current-Carrying Wires, 12.4 Electromagnetic Induction and Faraday's Law). Unit 12 of the current AP Physics 2 course and exam description, weighted 12 to 15% of the multiple-choice section at about 10 to 14 class periods. Eight learning objectives, all using the task verb describe, and one boundary statement, under Topic 12.2, limiting quantitative magnetic-force calculations to 0, 90 and 180 degrees while permitting qualitative analysis of other angles. AP Physics C: Electricity and Magnetism has a parallel Unit 12 adding the Biot-Savart law and Ampere's law, neither of which appears in the AP Physics 2 CED.

What the CED requires across Unit 12

Unit 12 of AP Physics 2 is Magnetism and Electromagnetism. The course description weights it at 12 to 15% of the multiple-choice section and estimates about 10 to 14 class periods. That is the same band as Units 13, 14 and 15. The first three units are weighted 15 to 18% each: Thermodynamics, then Electric Force, Field, and Potential, then Electric Circuits.

Four topics and eight learning objectives, and the equations are not spread evenly across them:

TopicLearning objectivesEquations in its required content
12.1 Magnetic Fields12.1.A, 12.1.B, 12.1.Cnone
12.2 Magnetism and Moving Charges12.2.A, 12.2.B1
12.3 Magnetism and Current-Carrying Wires12.3.A, 12.3.B2
12.4 Electromagnetic Induction and Faraday's Law12.4.A4

Every one of those eight objectives opens with the same task verb, "describe". The CED says that verb "encompasses the range of possible graphical, mathematical, or verbal skill applications", so describing a magnetic field can mean drawing it, writing the algebra, or saying it in words, and the exam uses all three.

The CED frames the unit as building on electrostatic forces, fields, free charges and circuits by exploring the relationships between moving charges, the magnetic fields they generate, and the magnetic forces those fields exert on other moving charges. Its essential questions are everyday versions: how an induction stovetop heats a pan without heating the cooktop, why metal is dangerous inside an MRI machine, how an electric motor works.

One idea holds the whole unit together

Moving charge makes a magnetic field. A magnetic field pushes on moving charge. Change the magnetic flux through a loop and you drive a current around it. Every required statement in Unit 12 is a version of one of those three sentences, which is why the unit is magnetism and electromagnetism: it is what electricity looks like once things start moving.

The CED builds the first two in matched pairs, once for a single particle and once for a wire.

  • Fields. 12.2.A.1 says a single moving charged object produces a magnetic field. 12.3.A.1 says a current-carrying wire produces one. A current is moving charge in bulk, so those are the same claim at two scales.
  • Forces. 12.2.B.2 says a magnetic field may exert a force on a charged object moving in that field. 12.3.B.1 says a magnetic field may exert a force on a current-carrying wire. Same claim, same two scales.
  • Induction. Topic 12.4 closes the circle: change the flux through a circuit and you get an induced emf, which drives a current, which is moving charge again.

Permanent magnets are not an exception. Essential knowledge 12.1.B.1 says magnetic dipoles result from the circular or rotational motion of electric charges, and that in magnetic materials this can be the motion of electrons. A bar magnet is not a different kind of object from a current loop; it is moving charge you cannot see.

One asymmetry with electrostatics is worth holding onto. Statement 12.1.A.1.i says magnetic fields can be produced by magnetic dipoles or combinations of dipoles, but never by monopoles. There is no magnetic equivalent of an isolated charge, which is why 12.1.A.2.i can say magnetic field lines form closed loops while an electric field line has to start or end on a charge.

How the four topics build

[12.1 Magnetic Fields](/ap-physics-2/unit-12-magnetism-and-electromagnetism/12-1-magnetic-fields) is the only topic in the unit whose required content names no equation. Its three objectives ask you to describe the properties of a magnetic field (12.1.A), the magnetic behavior of a material as a result of the configuration of its dipoles (12.1.B), and magnetic permeability (12.1.C). The content is qualitative and dense: field lines and poles, then a three-way sort of materials into ferromagnetic (iron, nickel, cobalt, which can be permanently magnetized), paramagnetic (aluminum, titanium, magnesium, which interact weakly and do not stay aligned), and diamagnetic, which the CED says applies to all materials. Vacuum permeability μ0\mu_0 is introduced here too, with the caution that the permeability of matter is not a constant for a material and varies with temperature, orientation and field strength.

[12.2 Magnetism and Moving Charges](/ap-physics-2/unit-12-magnetism-and-electromagnetism/12-2-magnetism-and-moving-charges) turns the field into a force. It gives you the magnitude,

FB=qvBsinθF_B = qvB\sin\theta

with θ\theta the angle between the velocity and the magnetic field, and the direction rule: the force is perpendicular to both the field and the velocity, as defined by the right-hand rule. Two extras sit here that are easy to miss. Statement 12.2.B.3 says a moving charge in a region with both a magnetic and an electric field experiences independent forces from each, and 12.2.B.4 introduces the Hall effect as the potential difference created in a conductor by an external magnetic field with a component perpendicular to the direction the charges are moving.

[12.3 Magnetism and Current-Carrying Wires](/ap-physics-2/unit-12-magnetism-and-electromagnetism/12-3-magnetism-and-current-carrying-wires) does both jobs for wires. The field of a long straight wire is

B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}

and the CED is precise about its shape: the field vectors are tangent to concentric circles centered on the wire, with no component toward, away from, or parallel to it. The magnitude is proportional to the current and inversely proportional to the perpendicular distance from the wire's central axis, so it falls off as 1/r1/r, not 1/r21/r^2. Two more results live here: the field at the center of a current-carrying loop points along the loop's axis, and the field near several wires is found by vector addition. Then the force on a wire,

FB=IBsinθF_B = I\ell B\sin\theta

where \ell is the length of the portion of the wire actually inside the field and θ\theta is the angle between the current direction and the field direction.

[12.4 Electromagnetic Induction and Faraday's Law](/ap-physics-2/unit-12-magnetism-and-electromagnetism/12-4-electromagnetic-induction-and-faradays-law) is the payoff. Magnetic flux is the amount of the component of a magnetic field perpendicular to a cross-sectional area,

ΦB=BAcosθ\Phi_B = BA\cos\theta

with the area vector defined perpendicular to the plane of the surface. Faraday's law relates changing flux to induced emf, Lenz's law fixes the direction, and the rod-on-rails case gives motional emf E=Bv\mathcal{E} = B\ell v. One learning objective, four equations: the only topic in the unit with that shape.

The seven magnetism equations on the sheet

The Magnetism section of the AP Physics 2 equation sheet prints seven equations. Counted off the sheet, not recalled:

EquationWhat it is for
FB=qvBsinθF_B = qvB\sin\thetaforce on a charge moving in a field (12.2)
B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}field of a long straight current-carrying wire (12.3)
FB=IBsinθF_B = I\ell B\sin\thetaforce on a current-carrying wire in a field (12.3)
ΦB=BA\Phi_B = \vec{B} \cdot \vec{A}magnetic flux, vector form (12.4)
ΦB=BcosθA\Phi_B = \lvert \vec{B} \rvert \cos\theta \, \lvert \vec{A} \rvertmagnetic flux, component form (12.4)
E=ΔΦB/Δt\lvert \mathcal{E} \rvert = \lvert \Delta \Phi_B / \Delta t \rvertFaraday's law, magnitude of induced emf (12.4)
E=Bv\mathcal{E} = B\ell vmotional emf, rod on rails (12.4)

Vacuum permeability is not in that block; it sits in Constants and Conversion Factors:

μ0=4π×107 (Tm)/A\mu_0 = 4\pi \times 10^{-7}\ (\text{T} \cdot \text{m})/\text{A}

Two things you might expect are missing.

The signed form of Faraday's law is not printed. The sheet gives the absolute-value form only. The version carrying the minus sign, E=ΔΦB/Δt\mathcal{E} = -\Delta \Phi_B / \Delta t, appears in the framework under 12.4.A.4 as the statement of Lenz's law, but it is not what you are handed in May. So the direction of an induced current is always something you argue for, never something you read off.

There is no radius formula for a charge circling in a magnetic field. Nothing in the Magnetism block gives one and Topic 12.2 does not list one. The situation is still fair game: the CED's optional sample activities for this unit include a graphing task on radius versus speed for a circling charge. You get there by setting the magnetic force equal to the centripetal force the circular motion requires, a Physics 1 move applied to a Physics 2 force.

The CED says outright that the framework and the sheet are different lists: some equations are printed in the framework only to show the end result of a derivation students are expected to be able to do, which it labels Derived Equations. Motional emf is the interesting case. Statement 12.4.A.5 calls E=Bv\mathcal{E} = B\ell v a derived equation, and it is also printed on the sheet, so you may quote it but should still be able to get it from ΦB=BAcosθ\Phi_B = BA\cos\theta with a changing area. The full sheet is at the AP Physics 2 formula sheet.

Directions are the whole difficulty

Six of Unit 12's essential-knowledge statements name the right-hand rule: 12.2.A.1.ii, 12.2.B.2.ii, 12.3.A.1.iii, 12.3.A.1.iv, 12.3.B.1.ii and 12.4.A.4.ii, spread across three of the four topics. The magnitudes here are one-line arithmetic. The direction is where the difficulty sits.

The CED is blunt about this in its Preparing for the AP Exam notes for Unit 12: when you write or identify a justification, simply referencing an equation, law or physical principle is not sufficient, and the example it chooses is a right-hand-rule answer. Saying the force on a charged particle is to the right "because of the 'right-hand rule'" is not complete enough to earn free-response points. Lay out the steps from the principle to the claim: which vectors you put where, and which quantity you read off your thumb.

Four things make directions go wrong.

  1. Current means conventional current. The exam conventions printed with the Table of Information state it outright, unless a question says otherwise. Point your thumb the way positive charge would flow, not the way electrons drift.
  2. A negative charge reverses the answer. The CED states the direction rule without spelling out the sign case, so this one is on you. The force depends on the sign of qq, so an electron feels a force opposite to the one the right-hand rule gives for a proton with the same velocity in the same field. Work the rule for a positive charge, then flip it.
  3. Three equations, three different angles. In FB=qvBsinθF_B = qvB\sin\theta, θ\theta is between the velocity and the field. In FB=IBsinθF_B = I\ell B\sin\theta, θ\theta is between the current direction in the wire and the field. In ΦB=BAcosθ\Phi_B = BA\cos\theta, θ\theta is measured from the area vector, which the CED defines as perpendicular to the plane of the surface and directed outward from a closed surface. That last one is where the cosine comes from, and it is why a loop lying flat with the field pointing straight through it has maximum flux rather than zero.
  4. Draw the field before you use the rule. Statement 12.1.A.2 says a magnetic field is a vector quantity representable with vector field maps, and suggested skill 1.A for Topics 12.1 and 12.2 is creating diagrams. The page notation is a dot for a field pointing out at you and a cross for one going in. Sketch it, then put your hand on the sketch.

Algebra-based: where the CED draws the line

AP Physics 2 is an algebra-based introductory college-level course, equivalent to the second course in an introductory college sequence in algebra-based physics. Its prerequisites say students should have completed AP Physics 1 or a comparable introductory course and should have taken or be concurrently taking precalculus. That is the reason Unit 12 stops where it does, and knowing the stopping point saves study time.

Unit 12 carries exactly one boundary statement across its four topics, and it sits under Topic 12.2. It says that quantitative treatment of the magnitude of the magnetic force exerted by a magnetic field on a moving charge is limited to angles of 0, 90 and 180 degrees between the velocity and the magnetic field. It then adds that qualitative analysis of other angles is permitted.

Both halves are load-bearing. You will not be asked to compute qvBsin37qvB\sin 37^\circ, but you can absolutely be asked whether the force grows or shrinks as the angle moves away from 90 degrees, or to rank three scenarios, and that is routine. At the three permitted angles the sine is 1 at 90 degrees and 0 at 0 and 180 degrees, so the arithmetic collapses to either qvBqvB or zero. Note also that the statement is attached to Topic 12.2 and to the force on a moving charge; the CED prints no equivalent restriction on the wire equation in Topic 12.3.

What the Physics 2 course description does not contain is just as useful. The Biot-Savart law and Ampere's law appear nowhere in it. Those belong to AP Physics C: Electricity and Magnetism, whose own Unit 12, titled Magnetic Fields and Electromagnetism, runs 12.1 Magnetic Fields, 12.2 Magnetism and Moving Charges, 12.3 Magnetic Fields of Current-Carrying Wires and the Biot-Savart Law, and 12.4 Ampere's Law. Physics 2 keeps the first two topic names, replaces the calculus-based pair with one algebra-based topic on wires, and adds a separate topic on induction. The Physics 2 CED makes the same point from its side, saying its Unit 12 concepts are "greatly expanded upon" in AP Physics C: Electricity and Magnetism.

So if a textbook chapter hands you an integral over a current element or a closed line integral of the field, you are reading Physics C material. Not wrong physics, just not on your exam, and B=μ0I/(2πr)B = \mu_0 I / (2\pi r) is the printed result you use instead.

Traps that span more than one topic

No change, no emf. A loop parked in an enormous steady magnetic field has enormous flux and exactly zero induced emf. Faraday's law is about ΔΦB/Δt\Delta \Phi_B / \Delta t, and since ΦB=BAcosθ\Phi_B = BA\cos\theta there are three ways to change it: change BB, change the area AA of the circuit inside the field, or change the orientation θ\theta. Rotating coils, expanding loops and rods sliding on rails are the three standard setups, one per variable.

Lenz's law opposes the change, not the field. Statement 12.4.A.4.i says an induced emf generates a current that creates a magnetic field opposing the change in magnetic flux. If the flux is increasing, the induced field inside the loop points against the applied field. If the flux is decreasing, the induced field points with it, propping it up. Memorizing "opposes the field" gets every decreasing-flux case backwards.

A magnetic force does no work on a point charge. The CED does not state this as required content, but it follows from one that is: 12.2.B.2.ii says the force is perpendicular to the velocity. A force perpendicular to the displacement does no work, so a magnetic field alone changes a particle's direction, never its speed. Any question with a magnetic field speeding a particle up needs an electric field somewhere.

Electric and magnetic forces add independently. Statement 12.2.B.3 makes this explicit. The electric force acts on a charge whether or not it is moving; the magnetic force needs motion and depends on the angle. In a velocity-selector setup they can cancel, but as two separate vectors, not as one combined law.

A wire's field falls as 1/r1/r; a point charge's field falls as 1/r21/r^2. Doubling the distance from a long straight wire halves the field, but doubling the distance from a point charge quarters the electric field. Carrying the Coulomb's law instinct into Topic 12.3 loses functional-dependence questions, and functional dependence, skill 2.D, is suggested for Topics 12.3 and 12.4.

Breaking a magnet gives you two magnets. Statement 12.1.B.1.ii gives the example directly: break a bar magnet in half and both halves are dipoles. No north pole is ever found in isolation from a south pole.

How Unit 12 is assessed

The AP Physics 2 exam is 3 hours long and splits evenly. Section I is 42 multiple-choice questions in 85 minutes for 50% of the score. Section II is 4 free-response questions in 95 minutes for the other 50%, and the four are always one of each type: Mathematical Routines, Translation Between Representations, Experimental Design and Analysis, and Qualitative/Quantitative Translation. A four-function, scientific or graphing calculator is allowed on both sections.

With four free-response questions and seven units, a Unit 12 free-response question is not guaranteed in any given year. The reliable number is the multiple-choice weighting, 12 to 15%. The unit's AP Classroom Progress Check is about 18 multiple-choice questions and 4 free-response questions covering all four types.

The suggested skills the CED lists per topic are teaching suggestions rather than a promise about the exam, but they line up with the question styles worth rehearsing:

TopicSuggested skills
12.1 Magnetic Fields1.A, 2.C, 3.B, 3.C
12.2 Magnetism and Moving Charges1.A, 2.A, 2.C, 3.B
12.3 Magnetism and Current-Carrying Wires1.B, 2.A, 2.D, 3.A, 3.C
12.4 Electromagnetic Induction and Faraday's Law1.C, 2.B, 2.D, 3.C

Read down that table and the unit's shape shows. Topic 12.3 carries five suggested skills where the others carry four, and it alone lists 3.A, creating experimental procedures, and 1.B, quantitative graphs with scales and units, which fits a topic whose field you can measure against current and distance with a compass. Topic 12.4 is the only one listing 1.C, qualitative graph sketches, and 2.B, calculating an unknown quantity with units. So rehearse lab design and graph-plotting on wires, and sketching how flux and emf behave over time on induction.

Force on a proton crossing a magnetic field

A proton travels at 2.0×1052.0 \times 10^5 m/s through a uniform magnetic field of magnitude 0.40 T. Its velocity is perpendicular to the field. Find the magnitude of the magnetic force on the proton. Then state what the force would be if the proton instead moved directly along the field lines.

  1. Pick the equation. The Magnetism section of the sheet gives FB=qvBsinθF_B = qvB\sin\theta, where θ\theta is the angle between the velocity and the magnetic field.

  2. Check the angle against the boundary statement. Perpendicular means θ=90\theta = 90^\circ, one of the three angles Topic 12.2 permits quantitatively, so this is a legal calculation.

  3. Take the charge off the Table of Information rather than from memory: the elementary charge is e=1.60×1019e = 1.60 \times 10^{-19} C, and a proton carries +e+e.

  4. Substitute and multiply step by step. (1.60×1019)(2.0×105)=3.2×1014(1.60 \times 10^{-19})(2.0 \times 10^5) = 3.2 \times 10^{-14}, then (3.2×1014)(0.40)=1.28×1014(3.2 \times 10^{-14})(0.40) = 1.28 \times 10^{-14}, and sin90=1\sin 90^\circ = 1 leaves that unchanged, so FB=1.28×1014F_B = 1.28 \times 10^{-14} N.

  5. Round to the two significant figures the data supports: 1.3×10141.3 \times 10^{-14} N.

  6. For the second part, moving along the field lines means θ=0\theta = 0^\circ, and sin0=0\sin 0^\circ = 0, so the magnetic force is exactly zero. A charge moving parallel or antiparallel to a magnetic field feels no magnetic force at all.

FB=1.3×1014F_B = 1.3 \times 10^{-14} N when the proton moves perpendicular to the field, and FB=0F_B = 0 when it moves along the field. The direction of the non-zero force is perpendicular to both the velocity and the field, set by the right-hand rule, and because it is perpendicular to the velocity it changes the proton's direction without changing its speed.

Induced emf and current in a loop in a strengthening field

A single square loop of wire 0.20 m on a side lies in a uniform magnetic field that points straight through the loop, perpendicular to its plane. Over 0.25 s the field strength increases steadily from 0.10 T to 0.50 T. Find the magnitude of the induced emf. If the loop has a total resistance of 0.20 Ω\Omega, find the induced current, and state the direction of that current relative to the applied field.

  1. Find the area. A square 0.20 m on a side has A=(0.20 m)2=0.040 m2A = (0.20\ \text{m})^2 = 0.040\ \text{m}^2.

  2. Fix the angle. The field points straight through the loop, so it is parallel to the area vector, which the CED defines as perpendicular to the plane of the surface. That makes θ=0\theta = 0^\circ and cosθ=1\cos\theta = 1.

  3. Compute both fluxes from ΦB=BAcosθ\Phi_B = BA\cos\theta. Starting: (0.10 T)(0.040 m2)(1)=4.0×103(0.10\ \text{T})(0.040\ \text{m}^2)(1) = 4.0 \times 10^{-3} Wb. Final: (0.50 T)(0.040 m2)(1)=2.0×102(0.50\ \text{T})(0.040\ \text{m}^2)(1) = 2.0 \times 10^{-2} Wb.

  4. Subtract: ΔΦB=2.0×1024.0×103=1.6×102\Delta \Phi_B = 2.0 \times 10^{-2} - 4.0 \times 10^{-3} = 1.6 \times 10^{-2} Wb.

  5. Apply Faraday's law in the form the sheet prints, E=ΔΦB/Δt=(1.6×102 Wb)/(0.25 s)=0.064\lvert \mathcal{E} \rvert = \lvert \Delta \Phi_B / \Delta t \rvert = (1.6 \times 10^{-2}\ \text{Wb})/(0.25\ \text{s}) = 0.064 V.

  6. Get the current from Ohm's law as the sheet prints it, I=ΔV/R=(0.064 V)/(0.20 Ω)=0.32I = \Delta V / R = (0.064\ \text{V})/(0.20\ \Omega) = 0.32 A.

  7. Now the direction, which the sheet cannot give you. The flux through the loop is increasing, so by Lenz's law the induced current creates a magnetic field inside the loop that opposes that increase, meaning the induced field points opposite the applied field. Curl your right hand so your thumb points along the induced field; your fingers give the current direction around the loop.

E=0.064\lvert \mathcal{E} \rvert = 0.064 V and I=0.32I = 0.32 A. The induced current runs in the sense whose magnetic field inside the loop opposes the applied field, because the flux is increasing. Had the field been decreasing at the same rate, both magnitudes would be unchanged and the current would run the other way.

Frequently asked questions

How much of the AP Physics 2 exam is Unit 12?

Unit 12, Magnetism and Electromagnetism, is weighted at 12 to 15% of the multiple-choice section of the AP Physics 2 exam, and the course description estimates about 10 to 14 class periods for it. Units 13, 14 and 15 carry the same 12 to 15% weighting, while Units 9, 10 and 11 are each weighted 15 to 18%, so Unit 12 sits in the lighter of the two bands. The multiple-choice section is 42 questions and half the exam score.

What magnetism formulas are on the AP Physics 2 equation sheet?

The Magnetism section of the AP Physics 2 equation sheet prints seven equations: the force on a moving charge, F = qvB sin θ; the field of a long straight wire, B = μ₀I / 2πr; the force on a current-carrying wire, F = IℓB sin θ; magnetic flux in a vector form and a component form with cos θ; Faraday's law as the magnitude of the rate of change of flux; and motional emf, emf = Bℓv. Vacuum permeability, μ₀ = 4π × 10⁻⁷ (T·m)/A, sits separately in the Constants and Conversion Factors table.

Do you need the Biot-Savart law or Ampere's law for AP Physics 2?

No. Neither the Biot-Savart law nor Ampere's law appears anywhere in the AP Physics 2 course and exam description. They belong to AP Physics C: Electricity and Magnetism, which is calculus-based and has its own Unit 12 with topics named for both. In AP Physics 2 the field of a long straight wire is handed to you on the sheet as B = μ₀I / 2πr, and the field near several wires is found by vector addition rather than integration. If a resource gives you a line integral or an integral over a current element, it is teaching the Physics C course.

At what angles can AP Physics 2 make you calculate magnetic force?

Unit 12 has one boundary statement and this is it. Quantitative treatment of the magnitude of the magnetic force exerted by a magnetic field on a moving charge is limited to angles of 0, 90 and 180 degrees between the velocity and the magnetic field. The statement then adds that qualitative analysis of other angles is permitted, so you can still be asked whether the force increases or decreases as the angle changes, just not to compute a value at 37 degrees. At the three permitted angles the sine is 1 at 90 degrees and 0 at both 0 and 180 degrees.

What is the difference between Faraday's law and Lenz's law?

Faraday's law gives the size of the induced emf: it equals the rate at which the magnetic flux through the circuit changes. Lenz's law gives the direction: the induced emf drives a current whose own magnetic field opposes the change in flux that produced it. On the AP Physics 2 equation sheet only the magnitude form is printed, with absolute value bars and no minus sign, so the direction is never something you read off the sheet. The signed version appears in the course framework under essential knowledge 12.4.A.4, and you are expected to argue the direction in words on free-response questions.

Is saying 'by the right-hand rule' enough on an AP Physics 2 free-response?

No, and the course description says so directly in its exam-preparation notes for Unit 12. Simply referencing an equation, law or physical principle is not a sufficient justification, and the example the CED picks is exactly this one: stating that the force on a charged particle is to the right because of the right-hand rule is not a complete enough answer to earn free-response points. You are expected to explain the steps that lead from the principle to the claim, which in practice means naming which vector you point your fingers along and what your thumb then represents. Six essential-knowledge statements in Unit 12 invoke the right-hand rule, so this comes up repeatedly.