AP Physics 1 · Topic 1.1

Topic 1.1: Scalars and Vectors in One Dimension

Unit 1: Kinematics10-15% of the multiple-choice section

A scalar is described by magnitude only, like distance and speed. A vector needs magnitude and direction: position, displacement, velocity, and acceleration are all vectors. In one dimension you can drop the arrow notation, because the sign of the component completely describes its direction.

AP Physics: Unit 1 (topics 1.1 Scalars and Vectors in One Dimension). AP Physics 1 Unit 1, Topic 1.1, covering learning objectives 1.1.A (describe a scalar or vector quantity using magnitude and direction, as appropriate) and 1.1.B (describe a vector sum in one dimension). The CED lists four suggested skills for this topic: 1.A, 2.C, 3.B, and 3.C. Unit 1 is weighted at 10-15% of the multiple-choice section.

Scalars carry a size, vectors carry a size and a direction

The College Board draws the line in one sentence: scalars are quantities described by magnitude only, and vectors are quantities described by both magnitude and direction. Magnitude means the size of the quantity with its unit attached, so 55 m, 4.0 m/s, and 12 kg are all magnitudes. A vector is not fully specified until you also state which way it points.

The CED names the examples you are expected to sort correctly. Distance and speed are scalar quantities. Position, displacement, velocity, and acceleration are vector quantities. Notice how the list pairs up: distance is the scalar partner of displacement, and speed is the scalar partner of velocity. That pairing is why the words are not interchangeable, and why a question asking for speed wants a different number than one asking for velocity whenever the motion reverses.

The sorting test is mechanical. Ask whether the answer is still complete with no direction attached. The car moved 3.0 km stands on its own, so distance is a scalar. The car ended up 3.0 km from where it started immediately raises the question of which way, so displacement is a vector.

The scalar and vector list Topic 1.1 names

Six quantities are called out by name in the essential knowledge for this topic. Sort them once and the habit does the rest of the work all year.

QuantityScalar or vectorSymbol
DistanceScalardd
SpeedScalarvv
PositionVectorx\vec{x}
DisplacementVectorΔx\Delta \vec{x}
VelocityVectorv\vec{v}
AccelerationVectora\vec{a}

Scalars never take an arrow; vectors do, which is the notation rule below. The arrows come back off the moment you commit to components on a named axis, which is why the variable key on the equation sheet reads dd = distance, xx = position, vv = velocity or speed, and aa = acceleration with no arrows anywhere. The same letter vv can therefore stand for a scalar or for a vector component, depending on whether the problem cares about direction. Mass and time are scalars too, which is why nobody attaches a direction to 12 kg or 4.0 s. Every directed quantity you meet later, force, momentum, torque, angular velocity, obeys the rules you set up here, so the sorting habit is worth building now.

Vectors drawn as arrows, with lengths that mean something

The CED asks you to model vectors visually as arrows whose direction matches the quantity and whose lengths are proportional to their magnitude. Proportional is the working word: if you draw a 3.0 m/s velocity as a 1.5 cm arrow, then 6.0 m/s has to be 3.0 cm, not just a slightly longer arrow. State the scale on the diagram, for example 1 cm represents 2.0 m/s, and every reader can measure your arrows and recover your numbers.

This is suggested skill 1.A, create diagrams, tables, charts, or schematics to represent physical situations, one of four skills the CED lists for Topic 1.1. It pays off twice. A motion diagram made of scaled velocity arrows shows acceleration at a glance, because the arrows lengthen or shorten as you step through time. And the same discipline carries into Unit 2, where badly scaled arrows in a free-body diagram hide whether the forces balance. The free-body diagram builder enforces the scaling for you while the habit sets.

Arrow notation, and the one place you can drop it

Vectors are notated with an arrow above the symbol for that quantity, so the CED writes the velocity update rule as

v=v0+at\vec{v} = \vec{v}_0 + \vec{a}t

Along a single axis that notation is optional. Vector notation is not required for vector components along an axis, because in one dimension the sign of the component completely describes the direction of that component. Drop the arrows, add an axis subscript, and the CED calls the result a derived equation:

vx=vx0+axtv_x = v_{x0} + a_x t

That component form, not the arrow form, is what the AP Physics 1 equation sheet prints. So the plus or minus sign in front of vxv_x is doing exactly the work the arrowhead did in the diagram: it is not shorthand or an approximation, it is the full direction statement. The cost is that the sign only makes sense against a stated axis, so write down which way is positive before you write down a single number.

Adding vectors in one dimension

When determining a vector sum in a given one-dimensional coordinate system, opposite directions are denoted by opposite signs. That single rule turns vector addition into ordinary arithmetic, in three steps.

  1. Choose the axis and the positive direction. East, right, and up are conventional choices, but any consistent choice works.
  2. Write each vector with its sign. A 5.0 m step west on an east-positive axis is 5.0-5.0 m.
  3. Add algebraically. A 12.0 m step east then a 5.0 m step west gives (+12.0m)+(5.0m)=+7.0m(+12.0 \, \mathrm{m}) + (-5.0 \, \mathrm{m}) = +7.0 \, \mathrm{m}.

Report the result as a vector: magnitude 7.0 m, pointing east. Two traps live here. Adding the magnitudes instead, 12.0+5.0=17.012.0 + 5.0 = 17.0 m, gives the distance walked, which is a different quantity. And a sum of zero is a real answer: two equal and opposite velocities, +6.0+6.0 m/s and 6.0-6.0 m/s, add to zero even though neither one is zero. In two dimensions you break each vector into components first and then apply this same rule on each axis separately.

A minus sign is a direction, not a size

Magnitude is never negative. A velocity of 3.0-3.0 m/s and a velocity of +3.0+3.0 m/s have the same magnitude, so both correspond to a speed of 3.0 m/s; they differ only in which way the object travels. It follows that an object at 20-20 m/s is moving faster than one at +5.0+5.0 m/s, even though 20-20 is the smaller number. Compare magnitudes when the question asks how fast, and compare signs when it asks which way.

The same reasoning defuses the misconception the CED singles out in its Unit 1 overview: students who use negative acceleration exclusively to mean an object slowing down. A negative acceleration only means the acceleration points in the negative direction. Whether the object speeds up or slows down depends on how that sign compares with the sign of the velocity, and matching signs mean speeding up. Topic 1.2 works through both cases with numbers.

How Topic 1.1 is tested, and what to do next

The CED lists four suggested skills for this topic: 1.A, create diagrams, tables, charts, or schematics to represent physical situations; 2.C, compare physical quantities between two or more scenarios or at different times and locations in a single scenario; 3.B, apply an appropriate law, definition, theoretical relationship, or model to make a claim; and 3.C, justify or support a claim using evidence from experimental data, physical representations, or physical principles or laws. Those four sit beneath the three AP Physics 1 science practices, Creating Representations, Mathematical Routines, and Scientific Questioning and Argumentation. Unit 1 as a whole is weighted at 10-15% of the multiple-choice section.

Read that skill list as a study plan rather than a question format. The scalar-vector distinction is easy to state and easy to lose under time pressure, so practice it where it actually bites: comparing distance with displacement, scaling the arrows in a diagram, and choosing a positive direction before any arithmetic starts. Next, take the definitions into Topic 1.2, then pick up the constant-acceleration toolkit in the kinematic equations guide and the rest of the unit at the Unit 1 overview.

Distance and displacement for a two-leg walk

A student walks 12.0 m east, turns around, and walks 5.0 m west. Taking east as the positive direction, find the total distance walked and the displacement.

  1. Set the axis first. East is positive, so the first leg is +12.0m+12.0 \, \mathrm{m} and the second leg is 5.0m-5.0 \, \mathrm{m}.

  2. Distance is a scalar, so direction is ignored and the path lengths simply add: d=12.0m+5.0m=17.0md = 12.0 \, \mathrm{m} + 5.0 \, \mathrm{m} = 17.0 \, \mathrm{m}.

  3. Displacement is a vector sum, so opposite directions carry opposite signs: Δx=(+12.0m)+(5.0m)=+7.0m\Delta x = (+12.0 \, \mathrm{m}) + (-5.0 \, \mathrm{m}) = +7.0 \, \mathrm{m}.

  4. Finish the vector with a direction. The magnitude is 7.0 m and the sign is positive, so the displacement is 7.0 m east. Sense check: the student ends up 7.0 m east of the start, which is exactly what pacing out 12.0 m and coming back 5.0 m leaves you.

Distance 17.0 m, displacement +7.0 m, which is 7.0 m east. The second leg adds to the distance and subtracts from the displacement, which is the whole difference between a scalar and a vector.

Reading direction straight off the sign of a velocity

A ball is thrown straight up from the ground with an initial velocity of 12.0 m/s. Take up as positive. Find the velocity at t=1.00t = 1.00 s and at t=2.00t = 2.00 s, and state which way the ball is moving at each instant.

  1. Use the component form of the velocity equation on the vertical axis, vy=vy0+aytv_y = v_{y0} + a_y t. The sheet writes this equation with xx subscripts, and the CED notes that it can be used in any single dimension, so relabel the axis to match the motion. With up positive, vy0=+12.0m/sv_{y0} = +12.0 \, \mathrm{m/s} and ay=9.8m/s2a_y = -9.8 \, \mathrm{m/s^2}, because gravity points down, opposite the positive axis.

  2. About that 9.8. The CED's table of information gives g=9.8m/s2g = 9.8 \, \mathrm{m/s^2}, and its Unit 1 boundary statement says questions requiring a numerical value will use g10m/s2g \approx 10 \, \mathrm{m/s^2} while students are not penalized for correctly using 9.8 or 9.81. This site uses 9.8 throughout so its answers stay internally consistent.

  3. At t=1.00t = 1.00 s: vy=12.0+(9.8)(1.00)=12.09.8=+2.2m/sv_y = 12.0 + (-9.8)(1.00) = 12.0 - 9.8 = +2.2 \, \mathrm{m/s}. The sign is positive, so the ball is still rising, at a speed of 2.2 m/s.

  4. At t=2.00t = 2.00 s: vy=12.0+(9.8)(2.00)=12.019.6=7.6m/sv_y = 12.0 + (-9.8)(2.00) = 12.0 - 19.6 = -7.6 \, \mathrm{m/s}. The sign is negative, so the ball is now falling, at a speed of 7.6 m/s.

  5. Separate magnitude from direction. The speeds, 2.2 m/s and 7.6 m/s, are the magnitudes; the signs carry the entire direction statement. Nothing about the axis or the equation changed between the two instants, only the sign of the answer.

vy=+2.2m/sv_y = +2.2 \, \mathrm{m/s} (upward) at 1.00 s and vy=7.6m/sv_y = -7.6 \, \mathrm{m/s} (downward) at 2.00 s. One axis, one equation, and the flip in sign is the flip in direction.

Frequently asked questions

What is the difference between a scalar and a vector?

A scalar is described by magnitude only; a vector is described by both magnitude and direction. AP Physics 1 lists distance and speed as scalars, and position, displacement, velocity, and acceleration as vectors. If an answer would be incomplete without saying which way, the quantity is a vector.

Is speed a vector or a scalar?

Speed is a scalar. Velocity is its vector partner. A car at 25 m/s has a speed; a car at 25 m/s north has a velocity. Speed is also never negative, because it is a magnitude, while a velocity of -25 m/s simply points along the negative direction of your chosen axis.

Why can one-dimensional problems use plus and minus signs instead of arrows?

Because in one dimension the sign of a component completely describes the direction of that component, so the arrow adds nothing. The CED makes this explicit: vector notation is not required for components along an axis. That is why the equation sheet prints v_x = v_x0 + a_x t rather than the arrow form. The sign only means something once you have stated which direction is positive.

How do you add two vectors in one dimension?

Pick a positive direction, write each vector with the sign that matches its direction, then add the signed numbers. A 12.0 m displacement east plus a 5.0 m displacement west is +12.0 m plus -5.0 m, which is +7.0 m, or 7.0 m east. Adding the magnitudes instead gives 17.0 m, which is the distance traveled, not the vector sum.

Does a negative velocity mean an object is slowing down?

No. A negative velocity means the object moves in the negative direction of your axis, and nothing more. Slowing down is about the velocity and the acceleration having opposite signs. An object with velocity -4 m/s and acceleration -2 m/s^2 has two negatives that agree, so it is speeding up.