AP Physics 1 · Topic 2.6
Topic 2.6: Gravitational Force
Unit 2: Force and Translational Dynamics18-23% of the multiple-choice section
Topic 2.6 covers two descriptions of one force. Newton's law of universal gravitation gives the attractive pull between any two masses, proportional to each mass and inversely proportional to the square of the center-to-center distance. Near Earth's surface it reduces to weight, mass times g.
AP Physics: Unit 2 (topics 2.6 Gravitational Force). AP Physics 1 Unit 2, Topic 2.6, covering four learning objectives: 2.6.A, describe the gravitational interaction between two objects or systems with mass; 2.6.B, describe situations in which the gravitational force can be considered constant; 2.6.C, describe the conditions under which the magnitude of a system's apparent weight is different from the magnitude of the gravitational force exerted on that system; and 2.6.D, describe inertial and gravitational mass. The CED lists four suggested skills for this topic: 1.A, 2.A, 2.D, and 3.C. Unit 2 and Unit 3 share the course's largest weighting, 18 to 23 percent of the multiple-choice section, over about 22 to 27 class periods.
Two descriptions of one force
Topic 2.6 holds both gravity equations, and part of the work is knowing which one a question wants.
Newton's law of universal gravitation is the general statement. It describes the gravitational force between two objects or systems as directly proportional to each of their masses and inversely proportional to the square of the distance between the systems' centers of mass:
The local form is that same force evaluated near Earth's surface, where the distance to Earth's center barely changes over the height of a lab, so the force is effectively constant:
The CED calls the first a relevant equation and the second a derived equation, and the distinction shows up on exam day: only the universal form is printed on the AP Physics 1 equation sheet as a force equation. The product does appear there inside the potential energy line , but the statement that weight equals is one you write down yourself.
Learning objective 2.6.A asks you to describe the gravitational interaction between two objects or systems with mass. Objective 2.6.B asks when the force can be treated as constant, which is what licenses the second equation. Objectives 2.6.C and 2.6.D then cover apparent weight and the two meanings of mass.
Newton's law of universal gravitation
Four claims come with EK 2.6.A.1 and its sub-statements, and each is testable on its own.
- Attractive. Gravity only pulls. There is no repulsive case, which is the structural difference from Coulomb's law, where like charges repel.
- Along the center line. The gravitational force is always exerted along the line connecting the centers of mass of the two interacting systems.
- Acting at the center of mass. The gravitational force on a system can be considered to be exerted on the system's center of mass. That is why a free-body diagram shows one weight arrow leaving a single point rather than a fringe of arrows spread over the whole object.
- Mutual. The two masses enter symmetrically, so the pull on each object has the same magnitude and the opposite direction. That is a Newton's third law pair. The smaller object is not pulled less hard; it simply accelerates more, because the same force divided by a smaller mass gives a larger acceleration.
The constant is supplied on the Table of Information printed with the exam: . And is measured center to center, not surface to surface, which is the detail that decides most setup errors.
The inverse square, and predicting factors of change
Suggested skill 2.D for this topic is predicting new values or factors of change using functional dependence between variables, and the form of the equation makes gravity a natural place to ask for it. The force scales linearly with each mass and as the inverse square of the separation.
| Change | Effect on the gravitational force |
|---|---|
| Double one mass | Twice as large |
| Double both masses | Four times as large |
| Double the center-to-center distance | One quarter |
| Triple the distance | One ninth |
| Halve the distance | Four times as large |
| Double both masses and double the distance | Unchanged |
The last row is worth checking by hand: the masses contribute a factor of 4 and the distance contributes a factor of one quarter, and the two cancel.
One caution about . Because the distance runs center to center, lifting an object 100 m above the ground barely changes it. Earth's center is thousands of kilometers away, so the ratio shifts by far less than a percent and the force is indistinguishable from what it was. That is not an accident; it is precisely the condition for the constant-gravity approximation in the next section.
The gravitational field
EK 2.6.A.2 introduces the field idea, which the course reuses later for electricity: a field models the effects of a noncontact force exerted on an object at various positions in space.
The magnitude of the gravitational field created by a system of mass at a point in space is the ratio of the gravitational force exerted by the system on a test object of mass to the mass of that test object. As a derived equation:
Watch which mass survives. The test mass cancels, so the field belongs to the source and to the location, not to whatever you put there. That is the whole point of a field: describe once what Earth does to the space around it, then get the force on any object by multiplying by that object's mass.
EK 2.6.A.2.ii ties the field back to motion. If the gravitational force is the only force exerted on an object, the observed acceleration of the object, in , is numerically equal to the magnitude of the gravitational field strength, in N/kg, at that location. The two units are the same combination written differently, since and therefore . The Table of Information lists both readings of side by side for exactly that reason. The condition still matters: add a second force, such as air resistance or a normal force, and the acceleration no longer matches the field.
Weight, and the numbers for g
EK 2.6.A.3 defines the word. The gravitational force exerted by an astronomical body on a relatively small nearby object is called weight, with the derived equation .
EK 2.6.B.1 says when you are allowed to use it. If the gravitational force between two systems' centers of mass has a negligible change as the relative position of the two systems changes, the gravitational force can be considered constant at all points between the initial and final positions of the systems. Over a lab bench, a stairwell, or a cliff, that holds comfortably. Over an orbital radius it fails, and you return to the universal form.
Now the numbers, because three values of appear in the official materials and they do not conflict once you see what each is for.
- EK 2.6.B.2 states that near the surface of Earth, the strength of the gravitational field is N/kg.
- A boundary statement under Topic 1.3 says that for all situations in which a numerical quantity is required for , the value will be used, and that students will not be penalized for correctly using the more precise commonly accepted values of or .
- The Table of Information printed with the exam gives and N/kg.
So the exam's own working number is 10, the reference table's number is 9.8, and 9.8 or 9.81 also earn credit. Every worked answer on this site is computed with , which lands about two percent below what the 10 shortcut gives. Say which value you used and hold it for the whole problem.
Apparent weight
Learning objective 2.6.C asks for the conditions under which the magnitude of a system's apparent weight differs from the magnitude of the gravitational force on it, and the CED answers with a definition that catches most students out.
The magnitude of the apparent weight of a system is the magnitude of the normal force exerted on the system. A bathroom scale never measures the gravitational force on you. It measures how hard it is pushing up, and reports that. The two agree only when they happen to be equal.
- Acceleration separates them. EK 2.6.C.2 states it flatly: if the system is accelerating, its apparent weight is not equal to the magnitude of the gravitational force exerted on it. In an elevator accelerating upward the floor has to balance gravity and supply the upward net force, so the normal force exceeds and the scale reads high.
- Weightless does not mean gravity free. A system appears weightless when there are no forces exerted on the system or when the force of gravity is the only force exerted on the system. An astronaut in orbit is in the second case: gravity is acting, hard, and nothing else is, so no surface pushes on her and her apparent weight is zero.
- The equivalence principle. An observer in a noninertial reference frame is unable to distinguish between an object's apparent weight and the gravitational force exerted on the object by a gravitational field. Sealed in a windowless cabin, you cannot tell a floor that pushes because you are sitting on a planet from a floor that pushes because the ship is accelerating.
The arithmetic in these cases is normal-force arithmetic; how to find normal force works through the standard setups.
Inertial mass and gravitational mass
Learning objective 2.6.D asks you to describe two ideas that share a symbol and a unit but not a definition.
Inertial mass, or inertia, is a property that determines how much an object's motion resists changes when interacting with another object. It is the in , and you measure it by pushing something and watching how reluctantly it speeds up.
Gravitational mass is related to the force of attraction between two systems with mass. It is the and in the universal law, and you measure it by weighing.
Nothing in the structure of the two laws demands that the same number serve both roles, and yet inertial mass and gravitational mass have been experimentally verified to be equivalent. One consequence falls out in a single line. For an object in free fall the only force is gravity, so
and if the two masses are the same number they cancel, leaving with no reference to the falling object at all. That is why a heavy object and a light one, released together with air resistance negligible, fall with the same acceleration, and it is the same cancellation that makes EK 2.6.A.2.ii true.
How Topic 2.6 is tested, and what to do next
Four suggested skills accompany Topic 2.6 in the CED: 1.A, create diagrams, tables, charts, or schematics to represent physical situations; 2.A, derive a symbolic expression from known quantities by selecting and following a logical mathematical pathway; 2.D, predict new values or factors of change of physical quantities using functional dependence between variables; and 3.C, justify or support a claim using evidence from experimental data, physical representations, or physical principles or laws. Practice 1 supplies 1.A, Practice 2 supplies 2.A and 2.D, and Practice 3 supplies 3.C, the three practices being Creating Representations, Mathematical Routines, and Scientific Questioning and Argumentation.
Notice what the list leaves out: 2.B, the calculate-an-unknown skill, which several other topics in this unit do list. The emphasis here falls on representing, deriving, scaling, and arguing, which matches the shape of the content. A ratio question that never needs the value of fits this topic more naturally than a plug-in does.
Unit 2 is weighted at 18 to 23 percent of the multiple-choice section, with about 22 to 27 class periods suggested, a share matched in this course only by Unit 3. From here: Newton's second law is what you feed a gravitational force into, gravity supplies the centripetal force for orbits in Topic 2.9 and in the centripetal force guide, and the AP Physics 1 equation sheet shows exactly which gravity equations are printed for you.
Universal gravitation, and why you do not feel a nearby object pulling
Two lead spheres, one of mass 8.0 kg and one of mass 12 kg, are placed with their centers 0.25 m apart. (a) Find the magnitude of the gravitational force each exerts on the other. (b) Compare it with the gravitational force Earth exerts on the 8.0 kg sphere, using .
(a) Use the relevant equation for this topic, , with from the Table of Information. The 0.25 m is a center-to-center distance, which is what means here.
Numerator: . Denominator: . Their ratio is .
Multiply by : , so to two significant figures. It is attractive, and it acts along the line joining the two centers.
(b) Earth's pull on the 8.0 kg sphere is its weight: , which is 78 N to two significant figures.
Take the ratio before rounding, so the rounding in each force does not compound: .
Both forces obey the same law, and the distance term actually works against Earth here, since its center is thousands of kilometers away rather than 0.25 m. Earth still wins by close to a billion, which tells you how completely its mass dominates the comparison. The two lead spheres do attract each other; the force is just far too small to notice.
(a) , attractive, along the line joining the centers. (b) Earth's pull on the same sphere is about 78 N, roughly times larger. That is the CED's own Unit 2 essential question answered with numbers: you feel pulled toward Earth and not toward a pencil because the two forces differ by hundreds of millions of times, not because one of them is missing.
Apparent weight, weightlessness, and the gravitational force
An astronaut of mass 68 kg is aboard a spacecraft at a location where the gravitational field strength has magnitude 8.7 N/kg. Take the direction toward Earth's center as positive, and work only the axis along the line to Earth's center. (a) Find the magnitude of the gravitational force on her. (b) The spacecraft coasts in orbit with gravity the only force acting on her. Find her apparent weight and her acceleration. (c) The engines then fire, and at one instant her acceleration is directed away from Earth's center. Find her apparent weight now.
(a) The field definition gives the force directly: , which is to two significant figures. Nothing about being in orbit switches gravity off.
(b) Apparent weight is the magnitude of the normal force exerted on the system (EK 2.6.C.1). Coasting in orbit, gravity is the only force on her, so no surface pushes on her and the normal force is zero. Her apparent weight is 0 N while the gravitational force on her is about 590 N. EK 2.6.C.3 names this case: a system appears weightless when the force of gravity is the only force exerted on it.
Her acceleration follows from EK 2.6.A.2.ii. With gravity the only force, the acceleration in is numerically equal to the field strength in N/kg, so , toward Earth's center. Check it against the second law: .
(c) Two forces now act along this axis: gravity toward Earth, , and the normal force from the floor pushing her away from Earth, . Her acceleration is directed away from Earth, so in this convention .
Apply the second law along the axis: , so , which is to two significant figures.
Her apparent weight went from 0 N to about 730 N while the gravitational force on her never moved from 590 N. That is EK 2.6.C.2 in one line: if the system is accelerating, its apparent weight is not equal to the magnitude of the gravitational force exerted on it.
(a) about . (b) Apparent weight 0 N, acceleration toward Earth's center. (c) Apparent weight about . Same astronaut and the same gravitational force throughout; only the normal force changed, and the normal force is what a scale reads.
Frequently asked questions
What is the difference between mass and weight?
Mass is a property of the object, measured in kilograms, and it does not change with location. Weight is a force, measured in newtons: the CED defines it as the gravitational force exerted by an astronomical body on a relatively small nearby object, found by multiplying mass by the local gravitational field strength. Move the same object to a place where the field is weaker and its mass is unchanged while its weight drops.
What value of g should I use on the AP Physics 1 exam?
A CED boundary statement says that where a numerical value of g is required, the exam will use about 10 meters per second squared, and that you will not be penalized for correctly using 9.81 or 9.8 instead. The Table of Information printed with the exam lists 9.8. Choose one, state which you used, and keep it for the whole problem. Every worked answer on this site uses 9.8.
Why do astronauts appear weightless if gravity is still pulling on them?
Because apparent weight is the normal force, not the gravitational force. The CED states that a system appears weightless when the force of gravity is the only force exerted on it. In orbit nothing pushes on the astronaut, so there is no normal force and her apparent weight is zero, while the gravitational force on her is still hundreds of newtons and is exactly what curves her path around Earth.
Is the equation for weight printed on the AP Physics 1 equation sheet?
Not as a force equation. Printed on the sheet you get Newton's law of universal gravitation plus the gravitational potential energy relationships, one of which does contain the mg product. The statement that weight equals mass times g is listed in the CED as a derived equation, so you produce it yourself, and the same goes for the field expression, g equals G times M divided by r squared.
Are newtons per kilogram and meters per second squared the same unit?
They are the same combination of base units, since one newton is one kilogram meter per second squared. The CED still keeps them apart in wording, because newtons per kilogram describes a gravitational field at a location while meters per second squared describes an object's acceleration. They are numerically equal only when the gravitational force is the only force acting.