Kinetic & Potential Energy Calculator (AP Physics 1)

Kinetic energy is K = (1/2)mv^2, the change in gravitational potential energy is mg times the change in height, and spring potential energy is (1/2)k(dx)^2, where dx is stretch from natural length. All three come out in joules when you use SI units, which the calculator above handles for you.

kinetic energy (K)

9 J

Speed enters squared, so K is never negative; doubling v quadruples K. 1 J = 1 kg m^2/s^2.

Steps

  1. 1.K = (1/2) m v^2 = 0.5 x 2 kg x (3 m/s)^2
  2. 2.K = 0.5 x 2 kg x 9 m^2/s^2 = 9 J

AP Physics: Unit 3 (topics 3.1 Translational Kinetic Energy, 3.3 Potential Energy). Covers Topics 3.1 and 3.3 of AP Physics 1 Unit 3 (Work, Energy, and Power), which carries 18 to 23 percent of the multiple-choice section. The same formulas appear in Unit 3 of AP Physics C: Mechanics.

What the calculator above computes

The calculator above handles the three energy formulas at the heart of AP Physics 1 Unit 3: translational kinetic energy K=12mv2K = \frac{1}{2}mv^2, change in gravitational potential energy ΔUg=mgΔy\Delta U_g = mg\Delta y, and elastic (spring) potential energy Us=12k(Δx)2U_s = \frac{1}{2}k(\Delta x)^2. Pick the quantity you need, enter the known values in SI units, and the result comes out in joules.

These three expressions are the building blocks of every energy bar chart and conservation of energy problem you will see this year. A block sliding down a ramp trades ΔUg\Delta U_g for KK. A dart gun trades UsU_s for KK. Getting fast and accurate with each formula on its own is the first step toward chaining them together in a full problem.

Kinetic energy depends on speed squared

Translational kinetic energy is the energy an object has because it is moving:

K=12mv2K = \frac{1}{2}mv^2

Mass mm goes in kilograms and speed vv in meters per second. Two features matter on the AP exam. First, KK scales linearly with mass but with the square of speed: doubling the mass doubles the kinetic energy, while doubling the speed quadruples it. That squared dependence is why highway crashes are so much worse than parking-lot crashes, and why braking distance grows faster than speed does. Second, KK is a scalar that can never be negative. Direction is irrelevant: a ball moving at 5 m/s east has exactly the same kinetic energy as one moving at 5 m/s west, because KK depends on v2v^2, so the sign of the velocity drops out. This is Topic 3.1 in the CED, and it pairs directly with the work-energy theorem.

Gravitational potential energy: only changes matter

Near Earth's surface, the AP Physics 1 equation sheet writes gravitational potential energy as a change:

ΔUg=mgΔy\Delta U_g = mg\Delta y

with g=9.8 m/s2g = 9.8\ \mathrm{m/s^2}. The deltas are deliberate. There is no single correct potential energy at a point, because you are free to call any height zero. Only the change in height between two positions has physical meaning, which is why the calculator above asks for a height change Δy\Delta y rather than an absolute height. If the object rises, Δy\Delta y and ΔUg\Delta U_g are both positive: the system gains stored energy. If it falls, both are negative, and the lost potential energy usually reappears as kinetic energy. One wording detail AP graders reward: potential energy belongs to the object-Earth system, not to the object by itself. A lone object cannot have gravitational potential energy.

Spring potential energy: stretch or compress, energy is stored

A spring that obeys Hooke's law, Fs=kΔxF_s = -k\Delta x, stores elastic potential energy

Us=12k(Δx)2U_s = \frac{1}{2}k(\Delta x)^2

where kk is the spring constant in newtons per meter and Δx\Delta x is the stretch or compression measured from the spring's natural (relaxed) length, in meters. Because Δx\Delta x is squared, the stored energy is positive whether you stretch or compress: 5 cm of compression stores exactly as much energy as 5 cm of stretch. The square also means storage is not proportional to displacement. Double the compression and you store four times the energy. The most common error is measuring Δx\Delta x from the wrong place: it is always the distance from the relaxed length, not from wherever the block happens to start. Spring energy comes back in Unit 7, where trading UsU_s for KK drives simple harmonic motion.

What a joule actually is

Every result from the calculator above comes out in joules (J), the SI unit of energy. One joule is the work done when a force of one newton pushes through one meter:

1 J=1 Nm=1 kgm2/s21\ \mathrm{J} = 1\ \mathrm{N \cdot m} = 1\ \mathrm{kg \cdot m^2/s^2}

To get a feel for the size, lift a 0.10 kg apple through 1.0 m: that stores (0.10)(9.8)(1.0)=0.98(0.10)(9.8)(1.0) = 0.98 J, almost exactly one joule. A 60 kg sprinter at 8.0 m/s carries 12(60)(8.0)2=1920\frac{1}{2}(60)(8.0)^2 = 1920 J. One food Calorie is 4184 J. Joules only appear if everything goes in as SI units: kilograms, meters per second, meters, and newtons per meter. Convert grams to kilograms and centimeters to meters before substituting, and the units take care of themselves.

Where these formulas lead on the AP exam

Unit 3 (Work, Energy, and Power) carries 18 to 23 percent of the AP Physics 1 multiple-choice section, and it rarely tests these formulas in isolation. The work-energy theorem connects work to kinetic energy: the net work done on an object equals its change in KK. Conservation of energy chains all three quantities together: for a system with no friction or external work, the total of KK, UgU_g, and UsU_s stays constant, so energy just shifts between the three buckets this page computes. Kinetic energy also decides how a collision is classified, since it is conserved only in elastic ones, the comparison that drives conservation of momentum problems. Power, covered by the work and power calculator, measures how fast that energy transfers: Pavg=W/ΔtP_{avg} = W/\Delta t. A reliable habit for multi-step problems: compute each energy term separately with the calculator above, then check that the before and after totals balance.

Kinetic energy of a highway car

A 1200 kg car travels at 25 m/s (about 56 mph). Find its kinetic energy.

  1. Write the formula: K=12mv2K = \frac{1}{2}mv^2.

  2. Substitute the values: K=12(1200 kg)(25 m/s)2K = \frac{1}{2}(1200\ \mathrm{kg})(25\ \mathrm{m/s})^2.

  3. Square the speed first: (25 m/s)2=625 m2/s2(25\ \mathrm{m/s})^2 = 625\ \mathrm{m^2/s^2}.

  4. Multiply through: K=(600 kg)(625 m2/s2)=375,000 JK = (600\ \mathrm{kg})(625\ \mathrm{m^2/s^2}) = 375{,}000\ \mathrm{J}.

K=3.75×105K = 3.75 \times 10^5 J (375 kJ). At half the speed, 12.5 m/s, the same car carries only 9.38×1049.38 \times 10^4 J, one quarter as much, because kinetic energy goes with speed squared.

Climbing stairs: change in gravitational potential energy

A 65 kg student climbs a staircase that raises her center of mass by 12 m. By how much does the gravitational potential energy of the student-Earth system increase?

  1. Write the formula: ΔUg=mgΔy\Delta U_g = mg\Delta y.

  2. Substitute: ΔUg=(65 kg)(9.8 m/s2)(12 m)\Delta U_g = (65\ \mathrm{kg})(9.8\ \mathrm{m/s^2})(12\ \mathrm{m}).

  3. Multiply mass by gg first: (65)(9.8)=637 N(65)(9.8) = 637\ \mathrm{N}, which is the student's weight.

  4. Multiply by the height change: (637 N)(12 m)=7644 J(637\ \mathrm{N})(12\ \mathrm{m}) = 7644\ \mathrm{J}.

ΔUg7.64×103\Delta U_g \approx 7.64 \times 10^3 J, or about 7640 J. The sign is positive because Δy\Delta y is positive: the system gained stored energy on the way up.

Energy stored in a dart gun spring

A dart gun spring with k=250k = 250 N/m is compressed 12 cm. How much elastic potential energy does it store, and how fast does a 0.050 kg dart leave if all of that energy becomes kinetic energy?

  1. Convert to SI units: Δx=12 cm=0.12 m\Delta x = 12\ \mathrm{cm} = 0.12\ \mathrm{m}.

  2. Apply the spring energy formula: Us=12(250 N/m)(0.12 m)2=12(250)(0.0144)=1.8 JU_s = \frac{1}{2}(250\ \mathrm{N/m})(0.12\ \mathrm{m})^2 = \frac{1}{2}(250)(0.0144) = 1.8\ \mathrm{J}.

  3. Set the stored energy equal to the dart's kinetic energy: 1.8 J=12(0.050 kg)v21.8\ \mathrm{J} = \frac{1}{2}(0.050\ \mathrm{kg})v^2.

  4. Solve for speed: v2=2(1.8)0.050=72 m2/s2v^2 = \frac{2(1.8)}{0.050} = 72\ \mathrm{m^2/s^2}, so v=8.5 m/sv = 8.5\ \mathrm{m/s}.

The spring stores Us=1.8U_s = 1.8 J, and the dart leaves at about v=8.5v = 8.5 m/s. This spring-to-kinetic handoff is the classic conservation of energy setup.

Frequently asked questions

Why does doubling the speed quadruple the kinetic energy?

Because speed is squared in the formula. If K = (1/2)mv^2 and you replace v with 2v, you get (1/2)m(2v)^2 = 4 times (1/2)mv^2. Mass, by contrast, enters linearly: double the mass and you only double the kinetic energy.

Can kinetic or potential energy be negative?

Kinetic energy can never be negative, because both mass and the square of speed are always positive or zero. Spring potential energy is also never negative, since the stretch is squared. The change in gravitational potential energy can absolutely be negative: whenever an object drops, delta y is negative and the object-Earth system loses stored energy.

What value of g does the calculator use?

It uses g = 9.8 m/s^2, matching the AP Physics 1 equation sheet. Use 9.8 (not 9.81) in your own exam work so your answers line up with the scoring guidelines.

What units should I enter to get joules out?

Use SI units everywhere: mass in kilograms, speed in meters per second, height change in meters, and spring constant in newtons per meter. Convert grams to kilograms and centimeters to meters before entering values. One joule equals one kilogram times meter squared per second squared.

Is Ug = mgh the same thing as delta Ug = mg delta y?

Yes. Writing U = mgh quietly assumes you have set the potential energy to zero at h = 0. The AP Physics 1 equation sheet writes it as a change, mg delta y, to emphasize that only differences in height matter physically. You can put the zero level anywhere convenient, and any consistent choice gives the same physics.